Y = x^3 + 6x^2 + 11;
y ' = (<span>x^3 + 6x^2 + 11) ' = 3x^2 + 12x
y ' = 0
3x^2 + 12x = 0 //:3
x^2 + 4x = 0
x*(x + 4) = 0
x = 0 ;
x = - 4
+ max - +
------------ ( - 4 ) ----------- ( 0 ) ---------> x
y ( - 4) = ymax = (-4)</span><span>^3 + 6*(-4)^2 + 11 = 43</span>
<span>интеграл от 0 до 4 (5-х2+4х-5)dx = (5х - х3/3 +4х2/2 - 5х) от 0 до 4 = (20-64/3 +32-20) - 0 = 32 - 21*1/3 = 10 и 2/3</span>