дано
V(C2H5OH) = 143.75 mL
p(C2H5OH) = 0.8 g/mL
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m(C2H5Br)-?
C2H5Br+NaOH-->C2H5OH+NaBr
m(C2H5OH) = V(C2H5OH) * p(C2H5OH) = 143.75 * 0.8 = 115 g
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 115 / 46 = 2.5 mol
n(C2H5Br) = n(C2H5OH) = 2.5 mol
M(C2H5Br)= 109 g/mol
m(C2H5Br) = n*M = 2.5 * 109 = 272.5 g
ответ 272.5 г
HClO₄ = H⁺ + ClO₄⁻
H₂SeO₄ = H⁺ + HSeO₄⁻, HSeO₄⁻ = H⁺ + SeO₄²⁻
HBr = H⁺ + Br⁻
NaOH = Na⁺ + OH⁻
NH₄OH = NH₄⁺ + OH⁻
Ca(OH)₂ = CaOH⁺ + OH⁻, CaOH⁺ = Ca²⁺ + OH⁻
Fe₂(SO₄)₃ = 2Fe³⁺ + 3SO₄²⁻
Mg(NO₃)₂ = Mg²⁺ + 2NO₃⁻
H₂SO₄ = H⁺ + HSO₄⁻, HSO₄⁻ = H⁺ + SO₄²⁻
CH3COO- + H+ + K+ + OH- = CH3COO- + K+ +H2O
H± + OH- = H2O