Question

Решите пожалуйста Log5(7-x)=log5(3-x)+1

Answer 1

$\displaystyle log_5(7-x)=log_5(3-x)+1\\\\ODZ: \left \{ {{7-x\ \textgreater \ 0} \atop {3-x\ \textgreater \ 0}} \right.; \left \{ {{7\ \textgreater \ x} \atop {3\ \textgreater \ x}} \right.; x\in (-oo;3)\\\\log_5(7-x)=log_5(3-x)+log_55\\\\log_5(7-x)=log_5(3-x)*5\\\\7-x=5(3-x)\\\\7-x=15-5x\\\\4x= 8\\\\x=2$