Question

(8 целых 7/12 минус 2 целых 17/36 ) * 2,7 -4 целых 1/3 Разделить на 0,65С решением!!!!!!!!

Answer 1

$(8\frac{17}{12}-2\frac{7}{36})*2.7-\frac{4\frac{1}{3}}{0.65}=\\\\=(8\frac{21}{36}-2\frac{17}{36})*2\frac{7}{10}-\frac{\frac{13}{3}}{\frac{65}{100}}=\\\\=6\frac{4}{36}*\frac{27}{10}-\frac{13*100}{3*65}=\\\\=\frac{220*27}{36*10}-\frac{13*20}{3*13}=\frac{22*9}{12}-\frac{20}{3}=\\\\=\frac{198}{12}-\frac{80}{12}=\frac{198-80}{12}=\frac{118}{12}=\frac{59}{6}=9\frac{5}{6}.$

Answer 2

$(8\frac{7}{12}-2\frac{17}{36})\cdot2,7-4\frac{1}{3}:0,65=(\frac{103}{12}-\frac{89}{36})\cdot\frac{27}{10}-\frac{13}{3}\cdot\frac{20}{3}=\\=\frac{103\cdot3-89}{36}\cdot\frac{27}{10}-\frac{20}{3}=\frac{309-89}{4}\cdot\frac{3}{10}-\frac{20}{3}=\frac{309-89}{4}\cdot\frac{3}{10}-\frac{20}{3}=\\=\frac{220}{4}\cdot\frac{3}{10}-\frac{20}{3}=\frac{33}{2}-\frac{20}{3}=\frac{99-40}{6}=\frac{59}{6}=9\frac{5}{6}$