1 ответ:
Читайте также
13.
a) При у= -1
cosx= -1
x=π+2πk, k∈Z
При к=2 x=π+2π*2=5π
б) При у=1/2
cosx=1/2
x₁=π/3 + 2πk, k∈Z
При к=2 x=π/3 + 2π*2 = π/3 + 4π = 13π/3
x₂= -π/3 + 2πk, k∈Z
При к=2 x= -π/3 + 2π*2= -π/3 + 4π = 11π/3
Ответ: 11π/3; 13π/3; 5π.
a) При у= -1
cosx= -1
x=π+2πk, k∈Z
При к=2 x=π+2π*2=5π
б) При у=1/2
cosx=1/2
x₁=π/3 + 2πk, k∈Z
При к=2 x=π/3 + 2π*2 = π/3 + 4π = 13π/3
x₂= -π/3 + 2πk, k∈Z
При к=2 x= -π/3 + 2π*2= -π/3 + 4π = 11π/3
Ответ: 11π/3; 13π/3; 5π.
-6x - 3x <span>≥ 13 - 7
-10x </span><span>≥ 6 (*(-1))
10x </span>
-6
<span>x </span> 0.6
-10x </span><span>≥ 6 (*(-1))
10x </span>
<span>x </span>