<span>фосфор <span>1s</span></span>² <span><span>2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>³<span><span><span>
</span></span></span><span>фтор <span>1s</span></span>² <span><span>2s</span></span>² <span><span>2p</span></span>⁵<span><span><span>
</span></span></span><span>аргон <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁶<span><span><span>
</span></span></span><span>алюминий <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>¹<span><span><span>
</span></span></span><span>сера <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁴<span><span><span>
</span></span></span><span>калий <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁶ <span><span>4s</span></span>¹
конешно Б....................
Название соли CaF2-Фторид кальция
<span>Дано:
V(H2O) = 36 л
Решение:
n(H2O) = 36 л / 22,4 л / моль = 1,6 моль</span>
2 - 570
1,6 - x
x = 570 * 1,6 / 2 = 456 кДж
<span>Ответ: 456 кДж</span>