U₁ =
![\frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
PV₁
U₂ =
![\frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
PV₂
Μ = 20×10⁻³ кг/моль
U₁ =
![\frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
× 50×10³ Па × 12×10⁻³ м³ = 900 Дж
U₂ =
![\frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
× 50×10³ Па × 15×10⁻³ м³ = 1125 Дж
ΔU = U₂ - U₁ = 1125 Дж - 900 Дж = 225 Дж
U =
![\frac{3}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B2%7D+)
×
![\frac{m}{M}](https://tex.z-dn.net/?f=+%5Cfrac%7Bm%7D%7BM%7D+)
× RT
T₁ =
![\frac{2 *U2*M}{3*m*R}](https://tex.z-dn.net/?f=+%5Cfrac%7B2+%2AU2%2AM%7D%7B3%2Am%2AR%7D+)
T₂ =
![\frac{2*U2*M}{3*m*R}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%2AU2%2AM%7D%7B3%2Am%2AR%7D+)
ΔT= T₂ - T₁
ΔT =
![\frac{2*U2*M}{3*m*R}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%2AU2%2AM%7D%7B3%2Am%2AR%7D+)
-
![\frac{2 *U2*M}{3*M*R}](https://tex.z-dn.net/?f=+%5Cfrac%7B2+%2AU2%2AM%7D%7B3%2AM%2AR%7D+)
= 45,1 K - 36,1 K = 9 K
Відповідь: ΔU = 225 Дж, ΔТ = 9 К
U=3/2 *pV => p=2U/3V=2*9*10³/3*1=6000 Па = 6 кПа.
Я тогда на листке напишу и тебе в дичку скину