M(C) = 12, M(H) = 1
w(C) = 75%, w(H) = 25%
HxCy
12y/(x+12y)=0,75
x/(x+12y)=0,25
12y=0,75(x+12y)
12y-9y=0,75x
y=0,25x
x=4y
H4C - формула
1. 2Na + C3H7OH = 2C3H7ONa + H2
2. С3Н7ОН + HBr = C3H7Br + H2O
3. <span>10 C3H7OH + 25 O2 = 30 CO2 + 4 H<span>20</span></span>
------- х л 13,35 г
2Al + 3Cl2 = 2AlCl3
------- 67,2 л 267 г
х:67,2=13,35:267
х= 3,36 л
Ответ: 3,36 л
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