Это одно уравнение?)
x/2-x/3=2
(3x-2x)/6=2
x/6=2
x=12
x^2+4x+4-5x+20=<span>(х-6)(х+6)
</span>x^2-x+24-x^2-26=0
-x-12=0
x=(-12)
1*2/8+2-3/8=2/8+16/8-3/8=(2+16-3)/8=15/8=1 7/8 (одна целая семь восьмых)
Х3-6х2+36х+6х2-36х+219-2х2-18=х3-2х2+234
1)5x/(x-10) + 20x/(x-10)²=(5x²-50x+20x)/(x-10)²=(5x²-30x)/(x-10)²=5x(x-6)/(x-10)²
2)5x(x-6)/(x-10)² : 4(x-6)/(x-10)(x+10)=5x(x-6)/(x-10)² * (x-10)(x+10)/4(x-6)=
=5x(x+10)/4(x-10)
3)5x(x+10)/4(x-10) -25x/(x-10)=(5x²+50x-25x)/(x-10)=(5x²+25x)/(x-10)=5x(x+5)/(x-10)