1. (√15+√5)*√15-(5/3)*√27=15+√75-(5/3)*3√3=15+5√3-5√3=15.
2. (3/(9-х²)+1/(х-3))/(х/(х²-6х+9))=(-3/((х-3)(х+3)+1/(х-3))/(х/(х-3)²)=
=(х/((х-3)(х+3))/(х/(х-3)²)=(х-3)/(х+3).
2) 4=a1+3d
36=a1+11d
8d=32
d=4
4=a1+3d
a1=4-3d=4-3*4=-8
7 - 2x ≥ 0
-2x ≥ -7
x ≤ 3,5 или х∈(-∞; 3,5]
<span> (x^2-2x)^2-7x^2+14x-8=0
x^2-2x=t
t^2-7t-8=0
t=-1
x^2-2x+1=0
x=1
t=8
x^2-2x-8=0
D=4+32=36
x12=(2+-6)/2=4 -2
x=-2
x=4</span>