HCl, CL(-1)
<span>Открой таблицу окисления, там будет ^^
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1.дано
mAl=4.5g
найти
m n (Al2S3)
решение
4.5g xg
2Al+3S=Al2S3
54g 150g
x=4.5*150/54=12.5g
n=m/M=12.5/150=0.08mol
ответ 12.5g и 0.08 моль Al2S3
2.дано
mCuO=4g
найти
m n (O2)
решение
4g xL
2Cu+O2=2CuO
128g 32g
x=4*32/128=1g
n=m/M=1/32=0.03mol
ответ 1г и 0.03моль О2
<span>Li</span>2<span>SiO</span>3<span> + 2NH</span>4<span>NO</span>3<span> + 2H</span>2<span>O --> H</span>2<span>SiO</span>3<span> + 2NH</span>4<span>OH + 2LiNO</span>3
<span>SiO</span>32-<span> + 2NH</span>4+<span> + 2H</span>2<span>O --> H</span>2<span>SiO</span>3<span> + 2NH</span>4<span>OH </span>
<span> </span>
CrCl3 + Cs2SiO3 + H2O =
2CrCl3 + 3Cs2SiO3 + 6H2O --> 2Cr(OH)3 + 3H2SiO3 + 6CsCl
<span>2CrCl</span>3<span> + 3Na</span>2<span>CO</span>3<span> + 3H</span>2<span>O --> 2Cr(OH)</span>3<span> + 3CO</span>2<span> + 6NaCl</span>
<span>2Cr</span>3+<span> + 3CO</span>32-<span> + 3H</span>2<span>O --> 2Cr(OH)</span>3<span> + 3CO</span>2
Если да то: хлорная кислота и марганцовая кислота