3y+x=12, y-4x+9=0, K(x,y)=?
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x+3y=12
-4x+y=-9
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x=12-3y
-4x+y=-9
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x=12-3y
-4(12-3y)+y=-9
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x=12-3y
-48+12y+y=-9
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x=12-3y
13y=48-9
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x=12-3y
13y=39
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x=12-3y
y=3
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x=12-3.3
y=3
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x=12-9
y=3
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x=3
y=3
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K(3,3)
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Если Уровнение такое 2*2=5-x тогда правильный ответ б
B4 = b1 * q^3
q^3 = b4/b1 = -54/2= - 27
<span>q = - 3</span>
1)12 - 6x² = ( 2x + 3)( 5 - 3x)
12 - 6x² = 10x - 6x² + 15 - 9x
- 6x² + 6x² - x = - 12 + 15
- x = 3
x = - 3
2) ( x + 7)( x - 8) - ( x - 9)( x+ 10) = 0
x² - x - 56 - ( x² + x - 90) = 0
x² - x - 56 - x² - x + 90= 0
- 2x = - 34
2x = 34
x = 17