F(x) = x^5+1 / 5+1 - 2x^2 / 2 +c
Ответ - sqrt1,21..............................
Sin210 * tg 240 * cos 330 = sin( 180+ 30) * tg(180+60) * cos(360 - 30) =
= sin(- 30) * tg 60 * cos(- 30) = - 1/2 * sgrt3 * sgtt3/2 = - 3/4 = - 0,75
<span>а) (3у</span>²<span>-3у+1)-(4у-2)= 3y</span>²-3y+1-4y+2=3y²-7y+3
<span>б) 4b</span>³(3b²+b)=4b^4(3b+1)<span>
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