4х+у=10
х+3у=-3
4х+у=10
х=-3-3у
4(-3-3у)+у=10
-12-12у+у=10
-11у=10+12
-11у=22
у=-2
Х=-3-3*(-2)=-3+6=3
<span>Ответ:3;-2</span>
(х - 6)(х + 0,5) = 0
х² - 6х + 0,5х - 3 = 0
х² - 5,5х - 3 = 0
2х² - 11х - 6 = 0
Ответ во вложении................
1) а(4+3а)
2) 10(-2м+3n)
3) 5a(a-3)
4) 3y(-2x+3y)
5) 0,5x(x2-5)
6) 4y(2x-y)
7) -mn(mn+1)
8) 9q3(2p-q)
1. 2(х-3)(x+1/2)/(x-3)(x+3)=(2x+1)/(x+3)=0
x≠3 x≠-3
x=-1/2
2. =3+4√3+4-2√12=7+4√3-4√3=7
3. (0.5x^4у^-3)^-2=(0.5x^4/y³) ^-2=(y³/0.5x^4)²=y^6/0.25x^8