1) (3c+1)/(c-1) +c= 3c+1+c²-c/(c-1)=(c²+2c+1)/(c-1)
2) (c+1)²/(c-1)* 1/(c+1)=(c+1)/(c-1)
1)(4х-4у)(4х+4у)
1)(2а-3в)(2а-3в)
дальше не помню извини
<span> ((-1)</span><span>^2)</span><span>^5-1^2=0
<span>(-1)^7+(-1)^4=0</span></span>
(m-1)(m³+m²+m+1)=
m^4+m³+m²+m-m³-m²-m-1
m^4-1
(2-S)16+8S+4S²+2S³+S^4=
32+16S+8S²+4S³+2S^4-16S+8S²+4S³+2S^4+S^5
S^5+4S^4+8S³+16S²+32
∫(3/x³ - √x)dx = ∫(3·x⁻³ - x^0.5)dx = 3x⁻²/(-2) - (x^1.5)/1.5 = -3/(2x²) - (2x√x)/3