Question

3х кв+5х-2=0 квадрат тендеу

Answer 1

$3 x^{2} +5x-2=0$
$D=b^{2} -4ac=5^{2}-4*3*(-2)=[tex]49$
$\sqrt{D}=7$
$x_{1}= \frac{-5+7}{6}= \frac{1}{3}$
$x_{2}= \frac{-5-7}{6}=-2$
$Otvet: \frac{1}{3};-2$