Question

Log2(х+1)+log2(х+3)=3 lg(2х2-4х+12)=lg х + lg(х+3) ПОМОГИТЕЕЕЕЕЕЕЕ

Answer 1

$log_{2}(x + 1)(x + 3 ) = log_{2}(8 ) \\ x {}^{2} + 4x + 3 - 8 = 0 \\ x {}^{2} + 4x - 5 = 0 \\ x1 = (- 4 + 6):2 = 1 \\ x2 = (- 4 - 6 ):2= -5$