<em>n(P) : n(Cl2) = 2:3 => n(Cl2) = n(P) :2 * 3 = 1,5 mol => V(Cl2) = Vm * n(Cl2) = (1,5 *22,4) l = 33,6 l.</em>
<em>Otvet: 3.</em>
<span>2CH₃COOH+Cu(OH)₂ =(СH₃CОО)₂Cu+2H₂O</span>
2CH₃COO⁻ + 2H⁺ + Cu(OH)₂ = 2CH₃COO⁻ + Cu²⁺ + 2H₂O
2H⁺ + Cu(OH)₂ = Cu²⁺ + 2H₂<span>O
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2СH₃COOH+СaO=(CH₃COO)₂Ca+H₂O
2CH₃COO⁻ + 2H⁺ + CaO = 2CH₃COO⁻ + Ca²⁺ + H₂O
2H⁺ + CaO = Ca²⁺ + H₂O
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Ответ:
N=15,05 * 10^23
V=56 л
Объяснение:
M(CO2) =Mr(CO2) =16*2+12=44
n(CO2)=m(CO2) /M(CO2)
n(CO2) =2,5моль
V(CO2) =n(CO2) * Vm
V(CO2) = 56 л
N(CO2) = n(CO2) * Na
N(CO2) = 15.05 * 10^23
Смотри тут два варианта:
а) 1) 2 СН4 =(t> 1500 C)> C2H2 + 3 H2
2) 3 C2H2 =(C(актив.) ; t = 400 -600 C)> C6H6
3) (a) C6H6 + Cl2 =(AlCl3)> C6H5Cl + HCl
3) (b) C6H5Cl + 2 NaOH = NaCl + C6H5ONa + H2O
3) (c) C6H5ONa + HCl = C6H5OH + NaCl
4) C6H5OH + 3 Br2 => C6H2OH(Br)3 + 3 HBr
б) 1) (a) CH4 + Cl2 =(УФ) > CH3Cl + HCl;
1) (b) 2 CH3Cl + 2 Na =(t)> CH3-CH3 + 2 NaCl
2) (a) CH3-CH3 + Cl2 =(УФ) > CH3CH2Cl + HCl
2) (b) CH3CH2Cl + 2 Na + CH3Cl = 2 NaCl + CH3-CH2-CH3
3) (a) C3H8 + Cl2 =(t)> C3H7Cl + HCl
3) (b) 2 C3H7Cl + 2 Na = C6H14 + 2 NaCl
4) C6H14 =(Al2O3, Cr2O3, t)> C6H6 + 4 H2
5) (a) C6H6 + Cl2 =(AlCl3)> C6H5Cl + HCl
5) (b) C6H5Cl + 2 NaOH = NaCl + C6H5ONa + H2O
5) (c) C6H5ONa + HCl = C6H5OH + NaCl
<span>6) C6H5OH + 3 HO-NO2 =(H2SO4(конц.) , t)> C6H2OH(NO2)3 + 3 H2</span>