1)(a-b)²=a²-2ab+b²;
2)x²-2xy+y=(x-y)²;
3)m²-3mn+n²=(невозможно);
4)(2n-3)²=4n²-12n+9;
5)буду писать ответы уже ладно сразу (a-2)²;
6)x²-2xy+y²;
7)(a-b)²;
8)невозможно
9)4-12k+9k²;
10)(a-3)²;
11)c²-2cd+d²;
12)(1-x)²;
13)(a-4)²;
14)4p²-4pq+q²;
15)(2a-1)²;
всё
Ответ:
x²+(1-3a)x+2a²-2=0
ax+bx+c=0
a=1; b=1-3a; c=2a²-2
=>D=(1-3a)²-4(2a²-2)=1-6a+9a²-8a²+8=a²-6a+9=(a-3)²
![\\\ x_{1,2}=\frac{-b(+-)\sqrt{D} }{2a} x_{1}=\frac{-(1-3a)+a-3}{2} =\frac{-1+3a+a-3}{2}=\frac{-4+4a}{2}=\frac{4(-1+a)}{2} = -2+2a\\ x_{2}=\frac{-1+3a-(a-3)}{2} =\frac{-1+3a-a+3}{2}=\frac{2a+2}{2}=\frac{2(a+1)}{2} =a+1 \\](https://tex.z-dn.net/?f=%5C%5C%5C+x_%7B1%2C2%7D%3D%5Cfrac%7B-b%28%2B-%29%5Csqrt%7BD%7D+%7D%7B2a%7D+x_%7B1%7D%3D%5Cfrac%7B-%281-3a%29%2Ba-3%7D%7B2%7D+%3D%5Cfrac%7B-1%2B3a%2Ba-3%7D%7B2%7D%3D%5Cfrac%7B-4%2B4a%7D%7B2%7D%3D%5Cfrac%7B4%28-1%2Ba%29%7D%7B2%7D+%3D+-2%2B2a%5C%5C+%C2%A0x_%7B2%7D%3D%5Cfrac%7B-1%2B3a-%28a-3%29%7D%7B2%7D+%3D%5Cfrac%7B-1%2B3a-a%2B3%7D%7B2%7D%3D%5Cfrac%7B2a%2B2%7D%7B2%7D%3D%5Cfrac%7B2%28a%2B1%29%7D%7B2%7D+%3Da%2B1+%5C%5C)
Ответ: x1=-2+2a; x2=a+1
Ответ:
Объяснение:
z1=6-2i
z2=3-4i
z1*z2=(6-2i)(3-4i)=18-24i-6i+8i²=18-30i+8*(-1)=10-30i