Question

10x<3√2,5<-x Помогите решить данную систему неравенств,пожалуйста!)))

Answer 1

$\left \{ {{3 \sqrt{2.5}\ \textgreater \ 10x } \atop {{3 \sqrt{2.5}\ \textless \ -x}} \right. =\ \textgreater \ \left \{ {{{3 \sqrt{2.5}\ \textgreater \ 10x} \atop {-{3 \sqrt{2.5}\ \textgreater \ x}} \right. =\ \textgreater \ \left \{ {{x\ \textless \ ({3 \sqrt{2.5})/10} \atop {x\ \textless \ -{3 \sqrt{2.5}}} \right. \\ x\in (-\infty;-{3 \sqrt{2.5})$