1 ответ:
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1
а)![b*b ^{1/10} *b ^{2/30} :b ^{5/6} =b ^{1+1/10+2/30-5/6} =b ^{(30+3+2-25)/30} =b ^{1/3} = \sqrt[3]{b}](https://tex.z-dn.net/?f=b%2Ab+%5E%7B1%2F10%7D+%2Ab+%5E%7B2%2F30%7D+%3Ab+%5E%7B5%2F6%7D+%3Db+%5E%7B1%2B1%2F10%2B2%2F30-5%2F6%7D+%3Db+%5E%7B%2830%2B3%2B2-25%29%2F30%7D+%3Db+%5E%7B1%2F3%7D+%3D+%5Csqrt%5B3%5D%7Bb%7D+)
b)(1+∛a)(1-∛a+∛a²)/(1+∛a) - ∛a=1-∛a+∛a²-∛a=1-2∛a+∛a²=(1-∛a)²
2
a)![3 \sqrt[4]{(5x)^3}](https://tex.z-dn.net/?f=3+%5Csqrt%5B4%5D%7B%285x%29%5E3%7D+)
b)12(2√2-√5)/[(2√2+√5)(2√2-√5)]=12(2√2-√5)/(8-5)=12(2√2-√5)/3=
=4(2√2-√5)
b)(∛3-∛2)/[(∛3-∛2)(∛9+∛6+∛4)=(∛3-∛2)/(3-2)=∛3-∛2
а)
b)(1+∛a)(1-∛a+∛a²)/(1+∛a) - ∛a=1-∛a+∛a²-∛a=1-2∛a+∛a²=(1-∛a)²
2
a)
b)12(2√2-√5)/[(2√2+√5)(2√2-√5)]=12(2√2-√5)/(8-5)=12(2√2-√5)/3=
=4(2√2-√5)
b)(∛3-∛2)/[(∛3-∛2)(∛9+∛6+∛4)=(∛3-∛2)/(3-2)=∛3-∛2