(cos(5π/2-α)- sin(α-π/2))(sin(π-α)+cos(3π-α))=(cos(2π+π/2-α)+sin(π/2-α))(sin(π-α)+cos(2π+π-α))=(cos(π/2-α)+sin(π/2-α))(sin(π-α)+cos(π-α))=(sinα+cosα)(sinα-cosα)=sin²α-cos²α=-(cos²-sin²α)=-cos2α=-cos(-π/8×2)=-cos(π/4)=-√2/2
<span>3x-2<2(5x-1)+7
3x-2<10x-2+7
3x-10x<2-2+7
-7x<7
x<-1
(- бесконечности; -1)</span>
Произведение равно нулю, если хотя бы один из множителей равен нулю
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