W(O)=Mr(O)/M(Ba(OH)2)
w(O)=16*2/171=18.7%
<span>Оно будет равно количеству молей серы.
</span>S → H2SO4<span>(S*490/H2SO4)/0.96 = 166.87 кг</span>
Ga2O3+6NaOH=2Ga(OH)3+3Na2O
Ga2O3+6HCl=2GaCl3+3H2O
дано
V(O2) = 2.24 L
------------------
m(HgO)-?
2HgO-->2Hg+O2
n(O2)= V(O2) / Vm = 2.24 / 22.4 = 0.1 mol
2n(HgO) = n(O2)
n(HgO) = 2*0.1 = 0.2 mol
M(HgO) = 217 g/mol
m(HgO) = n*M = 0.2 * 217 = 43.4 g
ответ 43.4 г