Question

Решите неравенства:

Answer 1

$1) 0.5^{ x^{2} -x} \ \textgreater \ \frac{1}{4}$
$\frac{1}{2}^{x^{2}-x} \ \textgreater \ \frac{1}{2}^{2}$
$x^{2} - x \ \textless \ 2$
x² - x - 2 < 0
x1 = 1; x2 = -2
x ∈ ( -1; 2 )

$2) 5^{2x} \ \textless \ 5^{-2}$
2x < -2
2x+ 2 < 0
2(x+1) < 0
x∈(-∞; -1)