Question

Сократить добь (3+2√2) ⁻⁻⁻⁻⁻⁻⁻⁻⁻ (1+√2)

Answer 1

$\frac{3+ 2\sqrt{2} }{1+ \sqrt{2} } = \frac{(3+ 2\sqrt{2})(1- \sqrt{2}) }{1-2 } =\\ =-(3+2 \sqrt{2} -3 \sqrt{2}-4 )=-(-1- \sqrt{2} )=1+ \sqrt{2}$