X(y+z)-(2y+2z)=x(y+z)-2(y+z)=(y+z)(x-2)
a(b-c)-(4b-4c)=a(b-c)-4(b-c)=(b-c)(a-4)
x(y-z)-(y-z)=(y-z)(x-1)
5(c-b)+(ab-ac)=5(c-b)-(-ab+ac)=5(c-b)-a(c-b)=(c-b)(5-a)
(√46 +1)² = 46 + 2√46 +1 = 47 + 2√46 = 23,5 + √46
Sin² 2x/3=3/4
(1-cos4x/3)/2=3/4
1-cos 4x/3=3/2
cos 4x/3=-1/2
4x/3=+-(π/3)+2πn
x=+-(π/4)+3/2πn
Решение
∛(1+x^4) = ∛(<span>1+x^2)
</span>[∛(1+x^4)]³ = [∛(<span>1+x^2)]</span>³
1 + x⁴ = 1 + x²
x⁴ - x² = 0
x² * (x² - 1) = 0
x₁ = 0
x² - 1 = 0
x² = 1
x₂ = - 1
x³ = 1
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