2x^2*(y-1)-x*(y-1)=(y-1)*(2x^2-x)=x*(y-1)*(2x-1)
sin(π/10 - x/2) = √2/2
π/10 - x/2 = (-1)^narcsin(√2/2) + πn, n∈Z
π/10 - x/2 = (-1)^n(π/4) + πn, n∈Z
x/2 = π/10 - (-1)^n(π/4) + πn, n∈Z
x = π/5 - (-1)^n(π/2) + 2πn, n∈Z
<span>(16*у^2-8*у+1)/(а+1)(1-4*у)=
=(1-4y)^2 / (a+1)*(1-4y)=
=(1-4y) / (a+1)
</span>
Решение задания смотри на фотографии