Ответ:
1) 2-метил,4-этилгексан
CaO, BaBr2, <span>NH3, бинарные</span>
<span><span><span>5H2O2</span> + <span>2KMnO4</span> + <span>3H2SO4</span> = 5O2↑ + K2SO4 + 2MnSO4 + 8H2O</span><span>
</span></span><span><span>Восстановление:<span>MnO4− + 8H+ + 5<span>e−</span> = Mn2+ + 4H2O | 2
</span>Окис:<span>H2O2 − 2<span>e−</span> = O2 + 2H+ |5</span></span><span>
</span></span><span>2MnO4− + 6H+ + 5H2O2 = 2Mn2+ + 8H2O + 5O<span>2
</span></span>
C4H6+H2=C4H8
C4H8+H2O=C4H9OH
C4H9OH=C4H8+H2O
Ответ: X-бутен-2, Y-бутанол-2