Question

Помогите решить. Подробнее пожалуйста

Answer 1

$1)8x {}^{2} - 4 - 2(5x - 2) \\ 2(4x {}^{2} - 2 - (5x - 2)) \\ 2(4x {}^{2} - 2 - 5x + 2) \\ 2x \times (4x - 5) \\ \\ 2)x {}^{2} - 16x = 0 \\ x \times (x - 16) = 0 \\ x = 0 \\ x - 16 = 0 \\ x = 0 \\ x = 16 \\ x {}^{1} = 0 \\ x {}^{2} = 16$