Ответ:
<h3>1)3H2SO4+2AL=AL2(SO4)3+3H2</h3><h3>AL2(SO4)3+NAOH=NA2SO4+ALOH3</h3><h3>2ALOH3=AL2O3+3H2O(РАЗЛОЖЕНИЕ)</h3><h3>2)FE+H2SO4=FESO4+H2</h3><h3>FESO4+NAOH=NASO4+FEOH3</h3><h3>FEOH3+6HCL=2FECL3+3H2O</h3><h3>FECL3=FE3+3CL</h3><h3>3)C+O2=CO2</h3><h3>CO2+NA2O=NA2CO3</h3><h3>NA2CO3+BA(OH)2=BaCO3+2NaOH</h3><h3>4)ZN+H2SO4=ZNSO4+H2</h3><h3>ZNSO4+CU=CUSO4+ZN</h3><h3>ZN+O2=ZNO</h3><h3>ZNO+2HNO3=ZN(N03)2+H2O</h3><h3>ZN(NO3)2+2NA(OH)=2NANO3+ZN(OH)2</h3><h3>ZN(OH)2=ZNO+H20</h3>
Объяснение:
Cu(OH)2 ↓ + MgO — Mg(OH)2 + CuO
Cu(OH)2 ↓ + MgO — Mg + 2OH + CuO
4FeS2+11O2=2Fe2O3+8SO2
n(FeS2)=5:120=0,04 моль
V(SO2)=0,04*2*22,4=1,792 л