Question

1) 2x³-50=0 2) 16x³+8x²+x=0

Answer 1

$2x^3-50=0\\2(x^3-25)=0\\x^3-25=0\\x^3=25\\x=+-\sqrt[3]{25}$

$16x^3+8x^2+x=0\\x(16x^2+8x+1)=0\\x=0$ или

$16x^2+8x+1=0\\D=64-4*16=0\\x=\frac{-8}{32} =-0,25$

Answer 2

1)

$2x {}^{3} = 50$

$x {}^{3} = 50$

$x = \sqrt[3]{25}$

2)

$x \times (16x {}^{2} + 8x + 1) = 0$

$x \times (4 + 1) {}^{2} = 0$

$x = 0$

$(4x + 1) {}^{2} = 0$

$x = 0$

$x = - \frac{1}{4}$