Question

( 2-√3)(2+√3) =

(5+√7)(5-√7)=

(6-2√5)(6+2√5)=

(11-3√4)(3√4+11)=

(2√3+3√2)(3√2-2√3)=

(2√7+5√2)(5√2-2√7)=

(3+√6)²=

(5-√3)²=

(2√7-5)²=

(2√10+1)²=

(√7+2√2)²=

(√6-3√2)²=

(2√3-5√2)²=

(6√2+2√3)²=

(√7+√2-1)²=

(√3+√5+1)²=

(√m-2)(√m+2)=

(3-√k)(3+√k)=

(√x+3√y)(3√y-√x)=

(2√k+√3t)(2√k-3√t)=

(a√a+1)(a√a-1)=

(√k+2ab)²=

(√m-3c)²=

(√a-√b)²=

(√p+√u)²=

Answer 1

( 2-√3)(2+√3)=2²-(√3)²=4-3=1