Question

36p^2 - (2p-1)^2Помогите, плиииииз❤ ❤ ❤ ❤ ❤ ❤ ❤ ❤ ​

Answer 1

Ответ:

$36p^2-(4p^2-4p+1)=36p^2-4p^2+4p-1=32p^2+4p-1=0$

$D=16+4*32*1=16+128=144=12$

$x[tex]x_{2} =\frac{-4-12}{2*32}=\frac{-16}{64} =\frac{1}{4}</p><p>$1=\frac{-4+12}{2*32} =\frac{8}{64} =\frac{1}{8}[/tex]

Объяснение: