Question

Решите систему неравенств:-х^2+х+6<=05-3(х+1)>х

Answer 1

Ответ:

(-беск.; -2] [3; +беск)

${x}^{2} - x - 6 \geqslant 0 \\ x1 + x2 = 1 \\ x1 \times x2 = - 6 \\ x1 = 3 \\ x2 = - 2$

--------------- - 2 --------------- 3 --------->х

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