1.149. ((x+3)/(x²-3x)+(x-3)/(x²+3x))·(9x-x³)/(x²+9)=
=((x+3)/x(x-3)+(x-3)/x(x+3))·x(9-x²)/(x²+9)=[((x+3)²+(x-3)²)/x(x²-9)]·x(9-x²)/(x²+9)=
=(x²+6x+9+x²-6x+9)·x·(9-x²)/(x(x²-9)·(x²+9)=(2·(x²+9)·x(9-x²))/(x·(x²-9)·(x²+9))=-2;
1.150 [(x+3)/(x-3)-(x-3)/(x+3)]:2x/(9-x²)=((x+3)²-(x-3)²)/(x²-9):2x/(9-x²)=
=(x²+6x+9-x²+6x-9)·(9-x²)/(2x·(x²-9))=(12x(9-x²)/2x(x²-9)=-6;
1.151 2a/(a+1)+(3/(a-1)²-3/(a²-1)):3/(a²-2a+1)=
=2a/(a+1)+[(3·(a+1)-3(a-1))/(a-1)²(a+1)]:3/(a-1)²=
=2a/(a+1)+(3a+3-3a+3)·(a-1)²/[3(a-1)²·(a+1)]=2a/(a+1)+6/3(a+1)=(2a+2)/(a+1)=2;
<span>1) 2,4*4 7/12=11
2) </span><span>2,25:1 1/8=2
3) 11-2=9</span>
1) 3,25-3/4= 3,25-0,75= 2,5
2) 2,5*6,25= 15,625
3) 2-0,75= 1,25
4) 1,25:4/5= 1,25:0,8= 1,5625
5) 15,625:1,5625= 10
6) 5,5-15/4= 5,5-3,75= 1,75
7) 1,75:5= 0,35
8) 2-0,8= 1,2
9) 1,2*3/4= 1,2*0,75= 0,9
10) 0,35:0,9=35/100:9/10= 7/20*10/9= 7/2*1/9= 7/18
11) 10+7/18= 10 7/18
Ответ: 10 7/18
Y'=4/2√x + 12 = 2/√х + 12
Решение смотри в приложении