Question

Решите пожалуйста)))

Answer 1

№1

а) (х+4)² = х²+2х*4+4² = х²+8х+16  б) (3b-с)² = (3b)²-2*3bc+c² = 9b²-6bc+c²  в) (2x+5)(2x-5) = 4x²-25  г) (y²-x)(y²+x) = y⁴-x²

№2

a)1/9-а² = 1/9*(1-9а²) = 1/9*(1-3а)(1+3а)  б)b²+10b+25 = b²+2b*5+5² = (b+5)²

№3

(a-2b)²+4b(a-b) = a²-4ab+4b²+4ba-4b² = a²  -(2/3)² = -4/9

№4

a) 3(1+2xy)(1-2xy) = 3(1-4x²y²) = 3-12x²y²  б) (x²-y³)² = (x²)²-2x²y³+(y³)² = x⁴-2x²y³+y⁶  в) (a+b)²-(a-b)² = 2b*2a = 4ab

№5

a) (4x-3)(4x+3)-(4x-1)²=3x = 16x²-9-16x²-8x+1=3x = -8x-3x-8 = -11x-8 = -11x=8 = x= -8/11

б) 16c²-49=0 = 16c²=49 = c=-7/4 , с=7/4

Answer 2

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