KMnO<span>4 + H2O2 + H2SO4 = O2 + K2SO4 + MnSO4 + H2O
</span><span>ОВР : </span>
<span>Восстановление: Mn+7 + 5e = Mn+2 5---- * 2
</span><span>Окисление: 2O- - 2e = O2 </span><span>2---- * 5
2</span>KMnO4 + 5H2O2 + 3H2SO4 = 5O2 + K2SO4 + 2MnSO4 + 8H2O
Na2O + 2HCl = 2NaCl +H2O
NaOH + HCl = NaCl +H2O
2NaOH + CuCl2 = Cu(OH)2 +2NaCl
Дано
W(H2SO4)=15%
NaOH
m(Na2SO4)=270 g
-----------------
m(H2SO4)-?
m(NaOH)-?
Y X 270
2NaOH+H2SO4-->Na2SO4+2H2O
2* 40 98 142
M(NaOH)=40 g/mol
M(H2SO4)=98 g/mol
M(Na2SO4)=142 g/mol
X=98*270 / 142
X=186.34 g
m(ppaH2SO4)=186.34 * 100% / 15%=548.06 g
Y(NaOH)=80*270 / 142
Y(NaOH)=152.11 g
ответ 548.06 г, 152.11 г
3K2SO3 + 2H3PO4 = 2K3PO4 + 3SO2 + 3H2O