В1 а)=а^3(-9б^2-3б)
б)=25с^2(-4x^2+4x-1)
1)2ax+bx-2ay-by=2a(x-y)+b(x-y)= (x-y)(2a+b)
2)2x^2+7x-4=2((x+1.75)^2-5.0625)=2((x+1.75+2.25)(x+1.75-2.25))=2((x+4)(x-0.5))
............................................
Ы, когда завтра экзамен:)
(1/
![a^{ \frac{1}{2} }](https://tex.z-dn.net/?f=+a%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+)
- 2)(a-4
![x^{ \frac{1}{2}} +2](https://tex.z-dn.net/?f=+x%5E%7B+%5Cfrac%7B1%7D%7B2%7D%7D+%2B2)
)
![^{ -\frac{1}{2} }](https://tex.z-dn.net/?f=%5E%7B+-%5Cfrac%7B1%7D%7B2%7D+%7D+)
((1-2a^1/2)/a^1/2)*(1/(a-4a^1/2+2)^1/2)
(1-2a^1/2)/a^1/2 / ((a-4a^1/2+2)^1/2)
1-2
![\sqrt{a} [(/tex] / a*(a^2-4a^1/2+2a))^1/2 1-2[tex] \sqrt{a}](https://tex.z-dn.net/?f=+%5Csqrt%7Ba%7D+%5B%28%2Ftex%5D+%2F+a%2A%28a%5E2-4a%5E1%2F2%2B2a%29%29%5E1%2F2+1-2%5Btex%5D+%5Csqrt%7Ba%7D+)
/ (a^2-4a^3/2+2a)^1/2
1-2
![\sqrt{a}](https://tex.z-dn.net/?f=+%5Csqrt%7Ba%7D+)
/ (a^2-4
![\sqrt{ a^{3} }](https://tex.z-dn.net/?f=+%5Csqrt%7B+a%5E%7B3%7D+%7D+)
+2a)^1/2
1-2
![\sqrt{a}](https://tex.z-dn.net/?f=+%5Csqrt%7Ba%7D+)
/ (a^2-4a
![\sqrt{a}](https://tex.z-dn.net/?f=+%5Csqrt%7Ba%7D+)
+2a)^1/2
Ответ: 1-2
![\sqrt{a}](https://tex.z-dn.net/?f=+%5Csqrt%7Ba%7D+)
/
![\sqrt{ a^{2}-4a \sqrt{a} +2a }](https://tex.z-dn.net/?f=+%5Csqrt%7B+a%5E%7B2%7D-4a+%5Csqrt%7Ba%7D+%2B2a+%7D+)
корень из 7 умножить на корень из 86 и делить на корень из 14=√86:√2=√43