А 27 не получился!___________
f'(x)=3x-π/2+4sinx
f'(π/6)=3*π/6-π/2+4sinπ/6=π/2-π/2+4*1/2=2
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
(х2+х+1)-(х2-х+1)=(х+1)2-(х-1)2=(х+1-х+1)(х+1+х-1)=4х
-7х2+х+(х+6х2)=-7х2+х+х+6х2=
-х2+2х=х(2-х)
(12-5p2) +(p3+2p2-p+15)=12-5p2+p3+2p2-p+15=p3-3p2-p+27=p3+27-3p2-p=(p+3)(p2-3p+9)-p(3p+p)