Question

помогите решить уравнения: 1)5,04:(104,2-x)=1,2 2)1,2x+4,5x-0,7=1,01

Answer 1

1) $5,04:(104,2-x)=1,2$

 

$104,2-x=5,04:1,2$

 

$104,2-x=4,2$

 

$x=100$

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$5,04:(104,2-100)=1,2$ (это проверка)

 

$5,04:4,2=1,2$

 

$1,2=1,2$

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2) $1,2x+4,5x-0,7=1,01$

 

$5,7x-0,7=1,01$

 

$5,7x=1,01+0,7$

 

$5,7x=1,71$

 

$x=1,71:5,7$

 

$x=0,3$

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$1,2\cdot0,3+4,5\cdot0,3-0,7=1,01$

 

$0,36+1,35-0,7=1,01$

 

$1,01=1,01$

Answer 2

1) $\frac{5.04}{104.2-x}=1.2$

125.04-1.2x=5.04

1.2x=120

x=100 

2) 1.2x+4.5x-0.7=1.01

5.7x = 1.71

x = 0.3