Question

!!! 1) log2 log9 3 =?? 2) log144 12 =??

Answer 1

$log_2log_93=log_2(log_{3^2}3)=log_2(\frac{1}{2}log_33)=log_2\frac{1}{2}=\\\\=log_22^{-1}=-1\cdot log_22=-1\cdot 1=-1\\\\\\log_{144}12=log_{12^2}12=\frac{1}{2}\cdot log_{12}12=\frac{1}{2}\cdot 1=\frac{1}{2}$