<span>Дано: l</span><span>o</span><span>=6м</span>
<span>∆l</span>=37мм<span>=0,037</span><span>м</span>
<span>α=12×10-6 K^-1</span>
<span>∆T-?</span>
<span>R=Ro(1+ α∆T), ρ=ρo(1+ α∆T), ∆T=(ρ-ρo)/ (ρo α)=(l-lo)/(lo α)=∆l/(lo α)</span>
<span>∆T=0,037</span><span>м</span><span>/(</span><span>6м×</span><span>12×10-6 K^-1)=514 K</span>