<span>2NaNO3+C=2NaNO2+CO2
·1 восстановитель
·2 окислитель
P2O3 + O2=P2O5
</span><span><span>·2 восстановитель
</span>
</span><span><span>·1 окислитель</span>
</span>
..........................
<span>2Li + 3H</span>2<span>SO</span>4<span> (конц.) = 2LiHSO</span>4<span> + SO</span>2<span>↑ + 2H</span>2<span>O</span>
<span><span>2H</span>2<span>O + 2Li = 2LiOH + H</span>2 <span>↑</span></span>
<span><span><span>2Li + Cl </span>2<span> = 2LiCl
Тут наверно ошибка не <span>iOH, а L<span>iOH
<span>Li</span>2<span>O + H</span>2<span>O = 2LiOH</span>
<span>LiOH + HCl (разб.) = LiCl + H</span>2<span>O</span>
</span></span></span></span></span>
1) CaO+3C=CaC₂+CO;
2) CaC₂+2H₂O⇒C₂H₂+Ca(OH)₂;
3) 3C₂H₂ ⇒(акт уголь)⇒ C₆H₆;
4) C₆H₆ +HNO₃ ⇒(H₂SO₄конц)⇒ C₆H₅NO₂+H₂0
5) C₆H₅NO₂+3Н₂ ⇒(Pt)⇒ C₆H₅NH₂+2H₂O
6) C₆H₅NH₂+3Br₂ ⇒ C₆H₅NH₂Br₃+ 3HBr