1 способ решения:
![2sin(2x-4 \pi )= \sqrt{3} \\ \\ sin(2x-4 \pi )= \frac{\sqrt{3}}{2} \\ \\ 2x-4 \pi =(-1)^n* \frac{ \pi }{3}+ \pi n \\ 2x=(-1)^n* \frac{ \pi }{3}+ \pi n+4 \pi \\ \\ x=(-1)^n* \frac{ \pi }{6}+ \frac{ \pi n }{2}+2 \pi =(-1)^n* \frac{ \pi }{6} + \frac{ \pi n }{2} \\ \\ OTBET: (-1)^n* \frac{ \pi }{6} + \frac{ \pi n }{2} , \ n \in Z](https://tex.z-dn.net/?f=2sin%282x-4+%5Cpi+%29%3D+%5Csqrt%7B3%7D++%5C%5C++%5C%5C+sin%282x-4+%5Cpi+%29%3D++%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D+%5C%5C++%5C%5C+2x-4+%5Cpi+%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B3%7D%2B+%5Cpi+n++%5C%5C+2x%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B3%7D%2B+%5Cpi+n%2B4+%5Cpi+++%5C%5C++%5C%5C+x%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B6%7D%2B+%5Cfrac%7B++%5Cpi+n+%7D%7B2%7D%2B2+%5Cpi++%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B6%7D+%2B+%5Cfrac%7B++%5Cpi+n+%7D%7B2%7D++%5C%5C++%5C%5C+OTBET%3A+%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B6%7D+%2B+%5Cfrac%7B++%5Cpi+n+%7D%7B2%7D+%2C+%5C+n+%5Cin+Z)
2 способ решения: (по формулам приведения sin(α-4π)=sinα)
![2sin(2x-4 \pi )= \sqrt{3} \\ 2sin2x= \sqrt{3} \\ \\ sin2x= \frac{ \sqrt{3} }{2} \\ \\ 2x=(-1)^n* \frac{ \pi }{3} + \pi n \\ \\ x=(-1)^n* \frac{ \pi }{6} + \frac{ \pi n}{2} \\ \\ OTBET: \ (-1)^n* \frac{ \pi }{6} + \frac{ \pi n }{2} , \ n \in Z](https://tex.z-dn.net/?f=2sin%282x-4+%5Cpi+%29%3D+%5Csqrt%7B3%7D++%5C%5C+2sin2x%3D+%5Csqrt%7B3%7D+%5C%5C++%5C%5C+sin2x%3D++%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D++%5C%5C++%5C%5C+2x%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B3%7D+%2B+%5Cpi+n+%5C%5C++%5C%5C+x%3D%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B6%7D+%2B+%5Cfrac%7B+%5Cpi+n%7D%7B2%7D+%5C%5C+%5C%5C+OTBET%3A+%5C+%28-1%29%5En%2A+%5Cfrac%7B+%5Cpi+%7D%7B6%7D+%2B+%5Cfrac%7B+%5Cpi+n+%7D%7B2%7D+%2C+%5C+n+%5Cin+Z)
4x+16y=4(x+4y)
3a²+a²=4a²
Решите уравнение
3x²+7x=0
х(3х+7)=0
х=0 или 3х+7=0
3х=-7
х=-7/3
Разложите на множители
2xyz-3x²z²+4y²z
=z(2xy-3x²z+4y²)
1)y=6x в квадрате - 10х - 1/х во второй степени
3)у= 2х умножить (1+х) - х в квадрате умножить на 1/ (1+х) в квадрате=
2х во второй +2х - х в квадрате / (1+х) в квадрате= х в квадрате - 2х / (1+х) в квадрате
4^2-3*4+c=0
16-12+c=0
c=-4
x^2-3x-4=0
D=9+16=25
x=(3+5)/2=4
x=(3-5)/2=-1