18-12=6 т - линия
18 - 100\%
6 - х\%
х=100:18*6=33\%
(5х + 3)(2х - 1) + 18 = 2(х - 3)² + 11х
10х² - 5х + 6х - 3 + 18 = 2х² - 12х + 18 + 11х
10х² + х + 15 = 2х² - х + 18
8х² + 2х - 3 = 0
D = 4 + 4•3•8 = 100
x1 = (-2 + 10)/16 = 8/16 = 0,5
x2 = (-2 - 10)/16 = -12/16 = -0,75
Ответ: х = -0,75; 0,5.
(5,2 * 10^(-3)) * (4.4*10^4) =
= 5.2*4.4 * 10^(-3+4) = 22.88 * 10^1
(3-√2)(3-√2)/(3+√2)(3-√2)=(3-√2)²/(9-2)=(9-6√2+2)/2=(11-6√2)/2