1)C3H7OH + 5O2= 3CO2 + 4H2O
2)CH3OH + CuO=CH2O +H2O + Cu
CH3 CH3
| |
3)CH3-CH2-C-CH3 + HCl=CH3-CH2-C-CH3 + H2O
| |
OH Cl
4)CH3OH+CH3OH=CH3-O-CH3+H2O
H2SO4
5)CH3-CH-CH2----------->CH3-CH=CH2 + H2O
| | 180` C
H OH
2H2+O2=2H20
n(O2)=M/Mr=16/32=0.5
КОЛИЧЕСТВО ВОДЫ-X
X/2=0.5/1
X=1
n(H20)=1
M(H20)=Mr*n=0.1*18=18
1. Мr(H3PO4) = 98
W(H) = 3/98=0.0306=3.06%
W(P) = 31/98 = 0.3163=31.63%
W(O) = 64/98 = 0.6531 = 65.31%
2. BaO - оксид бария
CuO - оксид меди(2)
K2O - оксид калия
3. а) ZnO + H2SO4<span>→ ZnSO4 + H2O
б) MgO + CO2 → </span>MgCO3<span>
в) MgO + </span>2HNO3 → Mg(NO3)2 + H2O <span>
г) </span>Al2O3 + 6HCl → 2AlCl3 + 3H2O <span>
д) BaO + SO2 → </span>BaSO3<span>
е) Na2O + H2O →2 NaOH</span>
56. Ответ В.
57.2HCl+Na2SO3=2NaCl+SO2+H2O
2H^+ + 2C^l- + 2Na^+ + SO3^2-=2Na^+ + 3Cl^- + SO2 + H2O
Fe^3+ + OH^ - = Fe(OH)3
Fe(NO3)3 + 3NaOH=Fe(OH)3+ 3NaNO3
Fe^3+ + 3NO3^- + 3Na^+ + 3OH^-= Fe(OH)3+ 3Na^+ + 3NO3^-