1) √x-1+√2-x=3
x-1+2√(x-1)(2-x)+2-x=9
-1+2√2x-x²-2+x+2=9
1+2√3x-x²-2=9
2√3x-x²-2=8
√3x-x²-2=4
3x-x²-2=16
3x-x²-2-16=0
-x²+3x-18=0
x²-3x+18=0
x=-(-3)±√(-3)²-4*1*18/2*1
x=3±√9-72/2
x=3±√-63/2
x∉R
2) √2x+5+⁴√x+2=0
√2x+5=-⁴√x+2
(2x+5)²=x+2
4x²+20x+25=x+2
4x²+20x+25-x-2=0
4x²+19x+23=0
x=-19±√361-368/8
x=-19±√-7/8
x∉R
<span>(sin^2t*cos^2t+cos^4t) / (1-sin^4t-sint*cos^2t)=
=[cos</span>²t(sin²t+cos²t)]/[(1-sin²t)(1+sin²t)-sint*cos²t)]=
=cos²t/[cos²t(1+sin²t)-sint*cos²t]=cos²t/[cos²t(1+sin²t-sint)]=1/(1+sin²t-sint)
Х принадлежит [-2,5; -1] и [2; +бесконечность]
(k-4)х²<span>+16х-24=0
(4-k)</span>х²-16х+24=0
D=256-4*24*(4-k)=256-384+96k=96k-128
96k-128>0
96k>128
k>4/3
k∈(4/3;4)∪(4;+∞)
ОДЗ
k≠4