А) основы -2, сорта мороженого - 5, украшения - 3.
N=2*5*3=30(рецептов).
б)Исключим те 2 коктейля, где мороженое украшено крошкой, и получим
N=30-2=28(рецептов).
1028.
х это время из А в Б
х+1 время назад
18х=12(х+1)
18х=12х+12
18х-12х=12
6х=12
х=12÷6
х=2 ч время из А в Б
2×18=36 км расстояние от А в Б
1029.
25х^3-9х=0
х(25х^2-9)=0
х1=0
25х^2-9=0
25х^2=9
х^2=9/25
х2=3/5
х3=-3/5
₩₩₩₩
х^5-81х=0
х(х^4-81)=0
х1=0
х^4-81=0
х^4=81
х2=-3
х3=3
Х^n+1/y^n-1*y^n+1/x^n+3 сток ибудет
1)
![y`(x)=(x^\frac{3}{2}+x^\frac{2}{3})`=\frac{3\sqrt{x}}{2}+\frac{2}{3x^\frac{1}{3}}](https://tex.z-dn.net/?f=y%60%28x%29%3D%28x%5E%5Cfrac%7B3%7D%7B2%7D%2Bx%5E%5Cfrac%7B2%7D%7B3%7D%29%60%3D%5Cfrac%7B3%5Csqrt%7Bx%7D%7D%7B2%7D%2B%5Cfrac%7B2%7D%7B3x%5E%5Cfrac%7B1%7D%7B3%7D%7D)
2)
![y`(x)=\frac{\frac{(3arcsin^2(x))(ln(\sqrt{x^2+1}))}{\sqrt{1-x^2}}-\frac{arcsin^3(x)}{x^2+1}}{ln^2(\sqrt{x^2+1})}](https://tex.z-dn.net/?f=y%60%28x%29%3D%5Cfrac%7B%5Cfrac%7B%283arcsin%5E2%28x%29%29%28ln%28%5Csqrt%7Bx%5E2%2B1%7D%29%29%7D%7B%5Csqrt%7B1-x%5E2%7D%7D-%5Cfrac%7Barcsin%5E3%28x%29%7D%7Bx%5E2%2B1%7D%7D%7Bln%5E2%28%5Csqrt%7Bx%5E2%2B1%7D%29%7D)
3)Если <span> y=2t+3, x=√t³+1, то:</span>
![\left\{ {{y=2t+3}\atop{x=\sqrt{t^3+1}}}\right\\ y`(x)=\frac{dy}{dx}\\ dy=y`(t)*dt\\ dx=x`(t)*dt\\ y`(x)=\frac{y`(t)*dt}{x`(t)*dt}=\frac{y`(t)}{x`(t)}\\ y`(t)=2\\ x`(t)=\frac{3t^2}{2\sqrt{t^+1}}\\ y`(x)=\frac{2*2\sqrt{t^+1}}{3t^2}=\frac{4\sqrt{t^+1}}{3t^2}](https://tex.z-dn.net/?f=%5Cleft%5C%7B+%7B%7By%3D2t%2B3%7D%5Catop%7Bx%3D%5Csqrt%7Bt%5E3%2B1%7D%7D%7D%5Cright%5C%5C%0Ay%60%28x%29%3D%5Cfrac%7Bdy%7D%7Bdx%7D%5C%5C%0Ady%3Dy%60%28t%29%2Adt%5C%5C%0Adx%3Dx%60%28t%29%2Adt%5C%5C%0Ay%60%28x%29%3D%5Cfrac%7By%60%28t%29%2Adt%7D%7Bx%60%28t%29%2Adt%7D%3D%5Cfrac%7By%60%28t%29%7D%7Bx%60%28t%29%7D%5C%5C%0Ay%60%28t%29%3D2%5C%5C%0Ax%60%28t%29%3D%5Cfrac%7B3t%5E2%7D%7B2%5Csqrt%7Bt%5E%2B1%7D%7D%5C%5C%0Ay%60%28x%29%3D%5Cfrac%7B2%2A2%5Csqrt%7Bt%5E%2B1%7D%7D%7B3t%5E2%7D%3D%5Cfrac%7B4%5Csqrt%7Bt%5E%2B1%7D%7D%7B3t%5E2%7D+)
Если <span> x=2t+3, y=√t³+1, то
</span>
![\left\{ {{y=2t+3}\atop{x=\sqrt{t^3+1}}}\right\\ y`(x)=\frac{dy}{dx}\\ dy=y`(t)*dt\\ dx=x`(t)*dt\\ y`(x)=\frac{y`(t)*dt}{x`(t)*dt}=\frac{y`(t)}{x`(t)}\\ x`(t)=2\\ y`(t)=\frac{3t^2}{2\sqrt{t^+1}}\\ y`(x)=\frac{3t^2}{2*2\sqrt{t^+1}}=\frac{3t^2}{4\sqrt{t^+1}}](https://tex.z-dn.net/?f=%5Cleft%5C%7B+%7B%7By%3D2t%2B3%7D%5Catop%7Bx%3D%5Csqrt%7Bt%5E3%2B1%7D%7D%7D%5Cright%5C%5C+y%60%28x%29%3D%5Cfrac%7Bdy%7D%7Bdx%7D%5C%5C+dy%3Dy%60%28t%29%2Adt%5C%5C+dx%3Dx%60%28t%29%2Adt%5C%5C+y%60%28x%29%3D%5Cfrac%7By%60%28t%29%2Adt%7D%7Bx%60%28t%29%2Adt%7D%3D%5Cfrac%7By%60%28t%29%7D%7Bx%60%28t%29%7D%5C%5C+x%60%28t%29%3D2%5C%5C+y%60%28t%29%3D%5Cfrac%7B3t%5E2%7D%7B2%5Csqrt%7Bt%5E%2B1%7D%7D%5C%5C+y%60%28x%29%3D%5Cfrac%7B3t%5E2%7D%7B2%2A2%5Csqrt%7Bt%5E%2B1%7D%7D%3D%5Cfrac%7B3t%5E2%7D%7B4%5Csqrt%7Bt%5E%2B1%7D%7D+)
pokjgj(hg<span>x ╫ </span>cos14<span>x = 1</span>