Периметр это сумма ддин всех сторон
НОД (168, 66) - (3*Х+13) = НОК (24,320)
6 - (3х +13) = 960
6 - 3х - 13 = 960
-3х = 960 - 6 + 13
-3х = 967
х= 967÷(-3)
х= -322,33(33)
• НОД (168, 66) = 2×3 = 6
168=2×2×2×3×7
66=2×3×11
• НОК (24, 320) = 2×2×2×2×2×2×5×3 = 960
320=2×2×2×2×2×2×5
24=2×2×2×3
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(1.75·2/5+1.75:1)·<span>1 5/7 = 4.2
1) </span>1.75·2/5 = 1.75·0.4 = 0.7
2) <span>1.75:1 = 1.75
</span>3) 0.7 + 1.75 = 2.45
4) 2.45 ·1 5/7 = 245/100 · 12/7 = 49/20· 12/7 = 21/5 = 4 1/5 = 4.2
(17/40-0,325):1/5·<span>0,4 = 0.1
</span>1) 17/40-0,325 = 17/40-3/8 = 17/40-15/40 = 2/40 = 1/20 = 0.05
2) 1/20 :1/5 = 5/20 = 1/4 = 0.25
3) 1/4·0,4 = 1/4·2/5 = 1/10 = 0.1
2,4х-11,2- 1,2+1.5х = 3,9х-10= 3,9 * 3 цел 1/13-10 = 12-10=2
ответ 2