А: Подставим координаты: 3 = 4 - 4 + 3
3 = 3 - Верно, значит А принадлежит графику функции
В: Подставим координаты: 5 = 1 + 2 + 3
5 = 6 - Неверно, значит В не принадлежит графику функции
Больше свойств вообще не помню
AB=AC/cosA;
cosA=√(1-sin²A)=√(1-64/81)=√(17/81)=(√17)/9
AB= \frac{2 \sqrt{17}}{( \sqrt{17}/9}=18
Преобразуем выражение в скобках:
![\frac{\sqrt{q}}{p-\sqrt{pq}}+\frac{\sqrt{p}}{q-\sqrt{pq}}=\frac{\sqrt{q}}{\sqrt{p}(\sqrt{p}-\sqrt{q})}+\frac{\sqrt{p}}{-\sqrt{q}(\sqrt{p}-\sqrt{q})}=\\=\frac{q-p}{\sqrt{q}\sqrt{p}(\sqrt{p}-\sqrt{q})}=\frac{-(p-q)}{\sqrt{q}\sqrt{p}(\sqrt{p}-\sqrt{q})}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bq%7D%7D%7Bp-%5Csqrt%7Bpq%7D%7D%2B%5Cfrac%7B%5Csqrt%7Bp%7D%7D%7Bq-%5Csqrt%7Bpq%7D%7D%3D%5Cfrac%7B%5Csqrt%7Bq%7D%7D%7B%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%2B%5Cfrac%7B%5Csqrt%7Bp%7D%7D%7B-%5Csqrt%7Bq%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%3D%5C%5C%3D%5Cfrac%7Bq-p%7D%7B%5Csqrt%7Bq%7D%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%3D%5Cfrac%7B-%28p-q%29%7D%7B%5Csqrt%7Bq%7D%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D)
![\frac{-(p-q)}{\sqrt{q}\sqrt{p}(\sqrt{p}-\sqrt{q})}*\frac{p\sqrt{q}+q\sqrt{p}}{p-q}=-\frac{\sqrt{p}\sqrt{q}(\sqrt{p}+\sqrt{q})}{\sqrt{q}\sqrt{p}(\sqrt{p}-\sqrt{q})}=-\frac{\sqrt{p}+\sqrt{q}}{\sqrt{p}-\sqrt{q}}=\\=-\frac{\sqrt{36}+\sqrt{4}}{\sqrt{36}-\sqrt{4}}=-\frac{8}{6}=-\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-%28p-q%29%7D%7B%5Csqrt%7Bq%7D%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%2A%5Cfrac%7Bp%5Csqrt%7Bq%7D%2Bq%5Csqrt%7Bp%7D%7D%7Bp-q%7D%3D-%5Cfrac%7B%5Csqrt%7Bp%7D%5Csqrt%7Bq%7D%28%5Csqrt%7Bp%7D%2B%5Csqrt%7Bq%7D%29%7D%7B%5Csqrt%7Bq%7D%5Csqrt%7Bp%7D%28%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%29%7D%3D-%5Cfrac%7B%5Csqrt%7Bp%7D%2B%5Csqrt%7Bq%7D%7D%7B%5Csqrt%7Bp%7D-%5Csqrt%7Bq%7D%7D%3D%5C%5C%3D-%5Cfrac%7B%5Csqrt%7B36%7D%2B%5Csqrt%7B4%7D%7D%7B%5Csqrt%7B36%7D-%5Csqrt%7B4%7D%7D%3D-%5Cfrac%7B8%7D%7B6%7D%3D-%5Cfrac%7B4%7D%7B3%7D)